leetcode 96 不同的二叉搜索树
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给定一个整数 n,求以 1 … n 为节点组成的二叉搜索树有多少种?

示例:

输入: 3
输出: 5
解释:
给定 n = 3, 一共有 5 种不同结构的二叉搜索树:

1
2
3
4
5
1         3     3      2      1
\ / / / \ \
3 2 1 1 3 2
/ / \ \
2 1 2 3

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class Solution(object):
def numTrees(self, n):
"""
:type n: int
:rtype: int
"""
if n == 1:
return 1
if n == 2:
return 2
if n == 3:
return 5
dp = [0 for i in range(n)]
dp[0] = 1
dp[1] = 2
dp[2] = 5
for i in range(3, n):
for j in range(i+1):
if j == 0:
dp[i] += dp[i-1]
elif j==i:
dp[i] += dp[i-1]
else:
dp[i] += dp[j-1] * dp[i-j-1]
return dp[-1]