leetcode SuperUglyNumber
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import java.util.HashMap;

public class SuperUglyNumber {
/**
* Write a program to find the nth super ugly number.
*
* Super ugly numbers are positive numbers whose all prime factors are in the given prime list primes of size k.
*
* Example:
*
* Input: n = 12, primes = [2,7,13,19]
* Output: 32
* Explanation: [1,2,4,7,8,13,14,16,19,26,28,32] is the sequence of the first 12
* super ugly numbers given primes = [2,7,13,19] of size 4.
* Note:
*
* 1 is a super ugly number for any given primes.
* The given numbers in primes are in ascending order.
* 0 < k ≤ 100, 0 < n ≤ 106, 0 < primes[i] < 1000.
* The nth super ugly number is guaranteed to fit in a 32-bit signed integer.
*/
public int nthSuperUglyNumber(int n, int[] primes) {
HashMap<Integer, Integer> idxs = new HashMap<>();
for (int i: primes){
idxs.put(i, 0);
}
int dp[] = new int[n];
for (int i=0; i<n; i++){
int min = Integer.MAX_VALUE;
// int minPrime = 0;
for (int idx : idxs.keySet()){
if (min > dp[idx] * idx){
min = dp[idx]*idx;
// minPrime = idx;
}
}
dp[i] = min;
// idxs.put(minPrime, idxs.get(minPrime)+1);
for (int idx: idxs.keySet()){
if (dp[i] == idx*dp[idxs.get(idx)]){
idxs.put(idx, idxs.get(idx)+1);
}
}
}
return dp[primes.length-1];
}
}