leetcode solution 16 3Sum closest
z

Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.

1
2
3
4
For example, given array S = {-1 2 1 -4}, and target = 1.

The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).


1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
class Solution {
public int threeSumClosest(int[] nums, int target) {
Arrays.sort(nums);
int ans = nums[0] +nums[1] + nums[nums.length-1];

for(int i = 0; i<nums.length-2; i++){
int first = i+1;
int last = nums.length - 1;
while(first < last){
if(Math.abs(nums[first] + nums[last] + nums[i] - target) < Math.abs(target- ans)){
ans = nums[first] + nums[last] + nums[i];
}
if(nums[first] + nums[last] + nums[i] > target){
last --;
}
else{
first ++;
}

}
}
return ans;

}
}
  • using three pointer i first last , each time compare sum(i, first, last). if sum > target, moving first to the next, otherwise, moving last to the left next one.
  • Each time, we keep the closest sum to ans